Make Battleground star ratings based on damage alone
Damage is really the most accurate measure of a warrior's prowess; kills and wins rely mostly on luck. Make Battleground star ratings based on damage alone.
Comments
Marcus the Wise31
Also a suggestion for the corsair wheel quests:
Expecting players to win 3 sea battles in a row is ridiculous. Any noob can enter sea battle and screw up a winning streak—and, given the vaalor/sadar imbalance, this makes it ridiculously hard for vaalorians (while n00b sadars can just piggyback).
Paimon66641
Yes you can piggy-back off of others but isn't there a part to that where you have to kill 30 players? "> i highly doubt any noob can piggy-back that part of it ">
Marcus the Wise31
Paimon666,
Well yeah, the 30 player part makes a bit more sense, but you can do 100000 damage and then the guy you're fighting runs away at 10 health or something...and that noob on your team got all the kills.
Roanoa_Zoro43
+1
D3athKnight35
Well damage is partially luck too... for example, a witcher that has to fight vs a zerk will get more damage then a witcher fighting a paladin. And damage based battleground is already here if I'm correct DoT (and ToH, not sure about ToH).
Marcus the Wise31
D3athKnight,
We can't have it perfect, but we can come close.
Dealt damage correlates the most with a warrior's prowess: more than wins or kills.
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Expecting players to win 3 sea battles in a row is ridiculous. Any noob can enter sea battle and screw up a winning streak—and, given the vaalor/sadar imbalance, this makes it ridiculously hard for vaalorians (while n00b sadars can just piggyback).
Well yeah, the 30 player part makes a bit more sense, but you can do 100000 damage and then the guy you're fighting runs away at 10 health or something...and that noob on your team got all the kills.
And damage based battleground is already here if I'm correct DoT (and ToH, not sure about ToH).
We can't have it perfect, but we can come close.
Dealt damage correlates the most with a warrior's prowess: more than wins or kills.